线性代数第一章习题答案 联系客服

发布时间 : 星期二 文章线性代数第一章习题答案更新完毕开始阅读088fbe6eaf1ffc4ffe47acb8

?(b?a)(c?a)(d?a)(c?b)(d?b)1(c?bc?b)?a(c?b)221(d2?bd?b)?a(d?b)2

=(a?b)(a?c)(a?d)(b?c)(b?d)(c?d)(a?b?c?d).

方法二

11bbb241ccc241ddd241a1bbbb2341cccc2341dddd2341xxxx234记

aaa24构造矩阵D1?a2?D,

aa34,则D1是范德蒙德行列式,

其结果为D1?(b?a)(c?a)(c?b)(d?a)(d?b)(d?c)(x?a)(x?b)(x?c)(x?d),其中x3的系数为?(b?a)(c?a)(c?b)(d?a)(d?b)(d?c)(a?b?c?d).

由行列式的降阶展开法则知,D1?A15?xA25?x2A35?x3A45?x4A55,其中x3的系数

?A45?D,所以有D?(b?a)(c?a)(c?b)(d?a)(d?b)(d?c)(a?b?c?d),即

1aaa241bbb241ccc241ddd24?(a?b)(a?c)(a?d)(b?c)(b?d)(c?d)(a?b?c?d).

(3) 用数学归纳法证明 当n?2时,D2?xa2?1x?a1?x?a1x?a2,命题成立.

2n?1n?2?a1x???an?2x?an?1, 假设对于(n?1)阶行列式命题成立,即Dn?1?x则Dn按第1列展开

?1Dn?xDn?1?an(?1)n?10?1?1????00?x00??1?xDn?1?an?右边

x?1所以,对于n阶行列式命题成立.

7.计算下列各行列式:

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1134114121123a0b100d0a20?00c010cd001b00a3?00e00; 0a???000???an?10100?0an(1)

234; (2)00ea1112481?24?81xxx230(3)

111; (4)

0?01.

1011?302?2?20?1?1?11?3解 (1)原式

ci?c12i?2,3,4341?1?32?2?2?1?1 ?1r2?r110?32?4?2?10??4?1?1?1?16.

(2)依次按第二行、第三行、第四行降阶展开,有

abcde000e100d010c001b00?0aaeea?a?e.

22(3)由范德蒙德行列式的结果知,

1111111a100?012480a20?00?24?800a3?00xxx23?(x?1)(x?2)(x?2)(?2?1)(?2?2)(2?1)?12(x?1)(x?4).

2 (4)依次按第2,3,?,n?1行降阶展开,有

???000???an?10100?0an?a2a3?an?1a111an?a2a3?an?1(a1an?1).

8.计算下列各行列式(Dk为k阶行列式):

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xy0?000xy?00(1)D0x?00n?0?????;

000?xyy00?0x1?a1a2a3?ana11?a2a3?an(2)Dn?a1a21?a3?an;

????a1a2a3?1?an(3)Dn?det(aij),其中aij?|i?j|;

1?a11?1(4)D11?a2?1n????,其中a1a2?an?0;

11?1?anan(a?1)n?(a?n)nan?1(a?1)n?1?(a?n)n?1(5)Dn?1????;

aa?1?a?n11?1(提示:利用范德蒙德行列式的结果.)

anbn??(6)Da1b12n?c,其中未写出的元素都是0.

1d1??cndn解 (1)按第1列降阶展开,有

xy?00y0?000x?00xy?00D1n?x?????(?1)n?y?????xn?(?1)n?1yn.00?xy00?y000?0x00?xy1?a1a2a3?ana11?a2a3?an(2)Dn?a1a21?a3?an

????a1a2a3?1?an

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1?a1ri?r1i?2,?n?1?1??1na210?0a301?0???an00 ??11?n?ai?1ia210?0a301?0???an00?c1??ci?2i00?0

?1n?1??ai?1i.

(3)aij?i?j

011012?n?21?1?1?1?n?20?2?2?2?2n?3n?22101?n?311?1?1?n?300?2?2?2n?43210?n?4111?1???????n?1n?2n?3n?4?0????????????1111?00000?n?1Dn?det(aij)?23?n?1?1?1

ri?ri?1i?1,2,?,n?1?1?1?n?1?1?1

n?4000?2?2n?5ci?c1i?2,3,?n?1?1?n?1

?(?1)n?1(n?1)2. a10a2?0?an????00?an?1?an11?11?an0?0?an(4)Dnci?cni?1,2,?,n?1

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