发布时间 : 星期一 文章微机原理与接口技术-顾晖-习题参考答案更新完毕开始阅读2d748c256beae009581b6bd97f1922791688be8b
NOT AX NOT DX ADD AX,1 ADC DX,0 EXIT: MOV AH,4CH INT 21H CODE ENDS END START
;本程序未考虑溢出的情况。DATA SEGMENT A1 DW 5050H
A2 DW ? ;存A1的反码 A3 DW ? ;存A1的补码 DATA ENDS CODE SEGMENT
ASSUME CS:CODE,DS:DATA START: MOV AX,DATA MOV DS,AX MOV AX,A1 NOT AX
33
MOV A2,AX INC AX MOV A3,AX EXIT: MOV AH,4CH INT 21H CODE ENDS END START 12 20. 答： 21. 答：
DATA SEGMENT ;AT 5000H ORG 3481H DAT DB 12H DB ?,?,? DATA ENDS CODE SEGMENT
ASSUME CS:CODE,DS:DATA START: MOV AX,DATA MOV DS,AX MOV AL,DAT
34
NEG AL MOV DAT+1,AL MOV AL,DAT XOR AL,00001111B MOV DAT+2,AL MOV AL,DAT OR AL,11110000B MOV DAT+3,AL EXIT: MOV AH,4CH INT 21H CODE ENDS END START COUNT=1000 DATA SEGMENT ORG 1000H DAT DB 10 DUP
(12H,-5,-3,0,-128,56H,98H,4,128,200) ORG 2000H MINDAT DB ? DATA ENDS CODE SEGMENT
35
ASSUME CS:CODE,DS:DATA START: MOV AX,DATA MOV DS,AX LEA SI,DAT MOV CX,COUNT DEC CX MOV AL,[SI] NEXT: INC SI CMP AL,[SI] JLE ISMIN MOV AL,[SI] ISMIN: LOOP NEXT MOV MINDAT,AL EXIT: MOV AH,4CH INT 21H CODE ENDS END START 13 22. 答：
36