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[2.0·Ö]1. ÒÑÖª?fH (?-Al2O3 , s , 298 K) =£­1669?8 kJ¡¤mol-1£» ?fH(Fe2O3 , s , 298 K) =£­822?1 kJ¡¤mol-1£»

Ôò·´Ó¦Fe2O3(s) + 2Al(s) == ?-Al2O3(s) + 2Fe(s) µÄ?rH(298 K) = ¡£

[2.0·Ö]2. B´ú±íÈÎÒ»ÖÖ»¯Ñ§ÎïÖÊ£¬¦ÍBΪijһ»¯Ñ§·´Ó¦ÖУ¬¸ÃÎïÖʵĻ¯Ñ§¼ÆÁ¿Êý£¬Ôò»¯Ñ§·´Ó¦µÄͨʽ¿ÉÒÔ±íʾΪ0 =Ϊ ¡£

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B£¬ÆäÖз´Ó¦ÎïµÄ»¯Ñ§¼ÆÁ¿ÊýΪ £¬²úÎïµÄ»¯Ñ§¼ÆÁ¿Êý

[2.0·Ö]3. »¯Ñ§·´Ó¦ N2(g) + 3 H2(g) 2NH3(g)

ÖÐÈýÖÖÎïÖʵĻ¯Ñ§¼ÆÁ¿Êý¦Í(N2)= £¬¦Í( H2) = £¬¦Í(NH3) = ¡£ [2.0·Ö]4. ÒÑÖª25 ¡æʱC2H6(g)£¬C2H4(g)£¬H2(g)£¬mol-1£»µÄ?cH·Ö±ðΪ£­1559?88 kJ¡¤£­1410?97 kJ¡¤mol-1£»£­285?85 kJ¡¤mol-1£¬ÔòÏàͬζÈÏ·´Ó¦£ºC2H6(g) = C2H4(g) + H2(g)µÄ?rH= ¡£ [2.0·Ö]5. 25 ¡æʱC2H4(g)£¬H2(g)£¬C2H6(g)£¬mol-1£¬mol-1£¬µÄ?cH·Ö±ðΪ£­1411?0 kJ¡¤£­285?8 kJ¡¤

-1

£­1559?9 kJ¡¤mol£¬Ôò·´Ó¦C2H4(g) + H2(g) == C2H6(g)ÔÚ25 ¡æµÄ?rH= ¡£ [2.0·Ö]6. 25¡æʱH2O(l)¼°H2O(g)µÄ±ê׼Ħ¶ûÉú³ÉìÊ·Ö±ðΪ£­286 kJ¡¤mol-1¼°£­242 kJ¡¤mol-1¡£ÔòË®ÔÚ25¡æʱµÄĦ¶ûÆø»¯ìÊ?vapHm = ¡£

[2.0·Ö]7. ÒÑÖªCH3OH(l) µÄ?cH(CH3OH , l , 298 K) =£­726?64 kJ¡¤mol-1£»HCHO(g)µÄ ?cH(HCHO , g , 298 K) =£­563?58 kJ¡¤mol-1£»ÔòÏÂÁз´Ó¦µÄCH3OH(l) + O2(g) == HCHO(g) + H2O(l)

µÄ?rH(298 K) = ¡£

[2.0·Ö]8. ÒÑÖª25 ¡æʱH2O(g)£¬CO(g)µÄ?fH·Ö±ðΪ£­241?84 kJ¡¤mol-1£¬mol-1£¬£­110?54 kJ¡¤

H2(g) + CO(g)µÄ?fH= ¡£ ÔòͬζÈÏ·´Ó¦ H2O(g) + C(ʯī)[2.0·Ö]9.ÒÑÖª£º?cH£¨CH3CHO , g , 298 K) =£­1193 kJ¡¤mol-1£» ?cH£¨C2H2 , g , 298 K) =£­1300 kJ¡¤mol-1£»

ÔòÔÚ298 KÏ£¬·´Ó¦ C2H2(g) + H2O(l) == CH3CHO(g) ÔÚ298 KʱµÄ?rH= ¡£ [2.0·Ö]10. ÒÑÖªÔÚ25 ¡æ

S(Õý½») + O2(g) == SO2(g)£¬ ?fH(SO2 ,g) =£­296?83 kJ¡¤mol-1£» S(Õý½») +

O2(g) == SO3(g)£¬ ?fH(SO3 ,g) =£­395?7 kJ¡¤mol-1£»

O2(g) == SO3(g)

Ôò·´Ó¦ SO2(g) +

ÔÚ25 ¡æʱµÄ ?fH= ¡£

[2.0·Ö]11. ÒÑÖªÆø̬±½ºÍҺ̬±½ÔÚ298 KµÄ±ê׼Ħ¶ûÉú³ÉìÊ·Ö±ðΪ82?93 kJ¡¤mol-1ºÍ49?03 kJ¡¤mol-1£¬Ôò298 K±½µÄĦ¶ûÆø»¯ìÊ?vapHm = ¡£

[2.0·Ö]12.ÒÑÖª£º?cH£¨C2H5OH , l , 298 K) =£­1368 kJ¡¤mol-1£» ?cH£¨C2H4 , g , 298 K) =£­1411 kJ¡¤mol-1£»

ÔòÔÚ298 KÏ£¬·´Ó¦ C2H4(g) + H2O(l) == C2H5OH(l) µÄ?rH= ¡£ [2.0·Ö]13.ÒÑÖª£º?fH(H2O , g , 298 K) =£­241?81 kJ¡¤mol-1£» ?fH(CO2 , g , 298 K) =£­393?51 kJ¡¤mol-1£» ÔòÔÚ298 KÏ·´Ó¦

C(ʯī) + 2H2O(g) === CO2(g) + 2H2(g) µÄ?rH= ¡£

[2.0·Ö]14. ÒÑÖª£º?cH(CH3COOH , l , 298 K) =£­874 kJ¡¤mol-1£» ?cH(C2H5OH , l , 298 K) =£­1368 kJ¡¤mol-1£»

ÔòÔÚ298 KÏ·´Ó¦£¬C2H5OH(l) + O2(g) == CH3COOH(l) + H2O(l) µÄ?rH= ¡£ £¨·´Ó¦²úÎï·Ö±ðΪ´¿ÒÒËáºÍ´¿Ë®£¬¼´Á½Õßδ»ìºÏ£¬²»±Ø¿¼ÂÇ»ìºÏìÊ¡££©

[2.0·Ö]15. ÒÑÖª25 ¡æʱC3H8(g)£¬C2H4(g)£¬CH4(g)£¬µÄ?cH·Ö±ðΪ£­2220?07 kJ¡¤mol-1£¬£­1410?97 kJ¡¤mol-1£¬£­890?31 kJ¡¤mol-1£¬ÔòͬζÈÏ·´Ó¦C3H8(g) == C2H4(g) + CH4(g)µÄ?rH= ¡£ Ò»¡¢Ìî¿Õ(¶þ)

[2.0·Ö]1. 25¡æʱ·´Ó¦H2(g) +

Cl2(g) === HCl(g) µÄDrH= £­92.3 kJ¡¤mol-1,ÈôÆøÌå¿É

¿´×÷ÀíÏëÆøÌ壬Ôò¸Ã·´Ó¦µÄDrU= ¡£

[2.0·Ö]2. ÒÑÖªDfH (SO2 , g , 298 K) =£­296.81 kJ¡¤mol-1£» DfH(H2S , g , 298 K) =£­20.50 kJ¡¤mol-1£» DfH (H2O , g , 298 K) =£­241.81 kJ¡¤mol-1£»

Ôò·´Ó¦2H2S(g) + SO2(g) == 2S(б·½) + 2H2O(g)µÄDrH(298 K) = ¡£ [5.0·Ö]3. ÒÑÖª·´Ó¦ Ag2O(s)+ 2HCl(g) == 2AgCl(s) + H2O(l) DrH(298 K) =£­324.9 kJ¡¤mol-1£»

-1

ÒÔ¼° DfH(Ag2O , s , 298 K) =£­30.56 kJ¡¤mol£» DfH(HCl , g , 298 K) =£­92.30 kJ¡¤mol-1£» DfH(H2O , l , 298 K) =£­285.84 kJ¡¤mol-1£»

Ôò AgCl(s)µÄ±ê׼Ħ¶ûÉú³ÉìÊ DfH(AgCl , s , 298 K) = ¡£

[1.0·Ö]4. ÔÚÈýÏàµã¸½½ü£¬H2OµÄĦ¶ûÕô·¢ìʺÍĦ¶ûÈÛ»¯ìÊ·Ö±ðΪ44.82 kJ¡¤mol-1ºÍ5.99 kJ¡¤mol-1£¬ÔòH2O(s)µÄĦ¶ûÉý»ªìÊΪ ¡£

[1.0·Ö]5. ÔÚÏàͬµÄζȺÍѹÁ¦Ï£¬·´Ó¦ B¡ª¡ú A µÄ·´Ó¦ìÊÊÇ DrH1£¬·´Ó¦ B ¡ª¡ú CµÄ·´Ó¦ìÊÊÇDrH2£¬Ôò·´Ó¦ A ¡ª¡ú C µÄ·´Ó¦ìÊÊÇDrH = ¡£

[1.0·Ö]6. ÆøÏ໯ѧ·´Ó¦ A(g) == 2B(g) ¿ÉÒԺܿì´ïµ½Æ½ºâ¡£ÔÚijһ¶¨Î¶ÈÏ£¬È¡nA,0 = 4 mol ÖÃÓÚÒ»´ø»îÈûµÄÈÝÆ÷ÖУ¬µ±ÒÔÉÏ·´Ó¦µÄ·´Ó¦½ø¶Èx= 3.2613 mol ʱ, ÈÝÆ÷ÖÐnB = ¡£ [3.0·Ö]7. ²úÎï T1£¬p1£¬V2 ·´Ó¦Îï T1£¬p1£¬V1 µÈΣ¬µÈѹ£¬DH1=Qp

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