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发布时间 : 星期一 文章CPU与汇编实验五实验报告更新完毕开始阅读51e9fdd8a26925c52cc5bffe

(2)、源代码

DATAS SEGMENT BUF DB 40

DB ? DB 40 DUP(0) SHUZI DB 10 DUP(0) BIAO DW 0

STRING DB 'input 10 numbers:$' DATAS ENDS

STACKS SEGMENT

STA DW 20H DUP(0) STACKS ENDS

CODES SEGMENT

ASSUME CS:CODES,DS:DATAS,SS:STACKS START:

main proc far MOV AX,DATAS MOV DS,AX MOV AX,STACKS MOV SS,AX

LEA BX,STRING ;输出 CALL output CALL HUICHE

CALL input ;输入10个十进制数 CALL HUICHE

CALL change ;将ASCII码转换 CALL paixu ;将其排序 LEA SI,BUF ADD SI,5 MOV DI,10 ABC:

MOV AL,[SI]

CALL output16 ;将16进制数输出 CALL kongge ADD SI,3 DEC DI JNZ ABC MOV AH,4CH INT 21H main endp

output proc near ;输出字符串 MOV DX,BX MOV AH,09H INT 21H RET

output endp

input proc near ;输入字符串 LEA DX,BUF MOV AH,0AH INT 21H RET input endp

HUICHE proc near ;回车换行 MOV DL,0DH MOV AH,02H INT 21H MOV DL,0AH MOV AH,02H INT 21H RET

HUICHE endp

change proc near ;ASCII码转换 LEA SI,BUF ADD SI,2 MOV CX,10 L1:

AND BYTE PTR [SI],0FH INC SI

AND BYTE PTR [SI],0FH ADD SI,2

LOOP L1 ;变成十进制 LEA SI,BUF ADD SI,2 MOV BL,10