发布时间 : 星期六 文章C++编程题更新完毕开始阅读91e4b2ea102de2bd960588dd
{
public: rectangle(int ,int ); friend int area(rectangle T); friend int fun (rectangle T); private: int len,wid; };
rectangle::rectangle(int a, int b) { len=a; wid=b; }
int area(rectangle T) { return (T.len*T.wid); }
int fun(rectangle T) { return (2*(T.len+T.wid)); }
int main() { rectangle R(20,30); cout<<\面积:\ cout<<\周长:\ return 0; }
19、定义一个复数类,用友元函数实现对双目运算符+和*的运算符重载,使其适用于复数运算。 #include
#include
#define err 0.00000001 double _x,_y; public:
CComplex(double x=0,double y=0):_x(x),_y(y){} CComplex operator+(const CComplex&z); CComplex operator*(const CComplex&z);
friend ostream&operator <<(ostream&os,const CComplex&z); friend istream&operator >>(istream&is,CComplex&z); };
int main() {
CComplex z1(0,1.2); CComplex z2(1,1.2); cout<
cout< CComplex CComplex::operator+(const CComplex&z) { CComplex c; c._x=_x+z._x; c._y=_y+z._y; return c; } CComplex CComplex::operator*(const CComplex&z) { CComplex c; c._x=_x*z._x-_y*z._y; c._y=_x*z._y+_y*z._x; return c; } ostream&operator <<(ostream&os,const CComplex&z) { if(fabs(z._x)>err) cout< if(fabs(z._y-1) cout<<(fabs(z._x)>err?\ else if(fabs(z._y+1) else if(z._y >err) cout<<(fabs(z._x)>err?\ else if(z._y<-err) cout< istream&operator >>(istream&is,CComplex&z) { is>>z._x>>z._y; return is; } 20、输入10 个同学的成绩,统计80分以上和不及格的人数,并输出平均值。 #include 21、声明一个类String1,其数据成员为char head[100],构造函数String(char *Head)实现head的初始化,成员函数void Reverse()实现head内字符串的逆序存放,成员函数void Print()实现head内字符串的输出。 #include { public: String (char *Head); void Reverse(); void Print (); private: char head[100]; }; String::String(char *Head) { int i=0; char *p=Head; while(*p!='\\0') { head[i]=*p; i++; p++; } head[i]='\\0'; } void String::Reverse() { int i=0; char h[100],*p=head; while(*p!='\\0') p++; while(*p!=head[0]) { p--; h[i]=*p; i++; } h[i]='\\0'; while(i>=0) { head[i]=h[i]; i--; } } void String::Print() { char *p=head; for(;(*p)!='\\0';p++) cout<<(*p); cout< int main() { char *Head=\ String s(Head); cout<<\正序:\ s.Print(); s.Reverse(); cout<<\逆序:\ s.Print(); return 0; } 22编写程序形成如下矩阵。 ?1?2?A=?3??4??5 1111?1111??2111? ?3211?4321??#include int a[5][5]; int ii,jj; for (ii = 0; ii< 5; ii++) { for (jj = 0; jj < 5; jj++) { if (ii - jj < 1) { a[ii][jj] = 1; } else { a[ii][jj] = ii+1 - jj; } } } for(ii=0;ii<5;ii++) { for(jj=0;jj<5;jj++) cout< } 23、定义盒子Box 类,要求具有以下成员:可设置盒子形状;可计算盒子体积;可计算盒子的表面积。 #include public: Box(double,double,double); double area(); double v(); private: double x,y,z; }; Box::Box(double x1,double y1,double z1) { x=x1; y=y1; z=z1; } double Box::area() { return (2*(x*y+y*z+x*z)); }