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西苑住宅小区10#、11#楼 专项施工方案
二、设计内容和步骤 1、现场勘探及初步设计:
(1)本工程所在施工现场范围内无各种埋地管线。
(2)现场采用380V低压供电，设一配电总箱，内有计量设备，采用TN-S系统供电。
(3)根据施工现场用电设备布臵情况，采用导线穿钢管埋地敷设，布臵位臵及线路走向参见临时配电系统图及现场平面图，采用三级配电，两级防护。
(4)按照《JGJ46-2005》规定制定施工组织设计，接地电阻R≤4Ω。 2、确定用电负荷: (1)、混凝土输送泵
Kx = 0.3 Cosφ = 0.7 tgφ = 1.02 Pjs = 0.3×32.2 = 9.66 kW
Qjs = Pjs× tgφ=9.66×1.02 = 9.86 kvar (2)、灰浆搅拌机
Kx = 0.5 Cosφ = 0.55 tgφ = 1.52 Pjs = 0.5×2.2 = 1.1 kW
Qjs = Pjs× tgφ=1.1×1.52 = 1.67 kvar (3)、塔式起重机
Kx = 0.2 Cosφ = 0.6 tgφ = 1.33
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西苑住宅小区10#、11#楼 专项施工方案
将Jc =40%统一换算到Jc1 =25%的额定容量 Pn = 48kW
Pe = n×(Jc/Jc1)×Pn = 1×(0.4/0.25)×48 = 60.72 kW Pjs = Kx×Pe =0.2×60.72 = 12.14kW Qjs = Pjs× tgφ=12.14×1.33 = 16.19 kvar (4)、蛙式夯土机
Kx = 0.5 Cosφ = 0.55 tgφ = 1.52 Pjs = 0.5×1.5 = 0.75 kW
Qjs = Pjs× tgφ=0.75×1.52 = 1.14 kvar (5)、插入式振动器
Kx = 0.3 Cosφ = 0.7 tgφ = 1.02 Pjs = 0.3×0.8 = 0.24 kW
Qjs = Pjs× tgφ=0.24×1.02 = 0.24 kvar (6)、平板式振动器
Kx = 0.3 Cosφ = 0.7 tgφ = 1.02 Pjs = 0.3×0.5 = 0.15 kW
Qjs = Pjs× tgφ=0.15×1.02 = 0.15 kvar (7)、钢筋调直机
Kx = 0.3 Cosφ = 0.7 tgφ = 1.02 Pjs = 0.3×4 = 1.2 kW
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西苑住宅小区10#、11#楼 专项施工方案
Qjs = Pjs× tgφ=1.2×1.02 = 1.22 kvar (8)、钢筋切断机
Kx = 0.3 Cosφ = 0.7 tgφ = 1.02 Pjs = 0.3×7 = 2.1 kW
Qjs = Pjs× tgφ=2.1×1.02 = 2.14 kvar (9)、钢筋弯曲机
Kx = 0.3 Cosφ = 0.7 tgφ = 1.02 Pjs = 0.3×3 = 0.9 kW
Qjs = Pjs× tgφ=0.9×1.02 = 0.92 kvar (10)、交流电焊机
Kx = 0.35 Cosφ = 0.4 tgφ = 2.29 将Jc =50%统一换算到Jc1 =100%的额定容量 Pn = Sn ×Cosφ = 9×0.4=3.6kW
Pe = n×(Jc/Jc1)×Pn = 1×(0.5/1)×3.6 = 2.55 kW Pjs = Kx×Pe =0.35×2.55 = 0.89kW Qjs = Pjs× tgφ=0.89×2.29 = 2.04 kvar (11)、木工圆锯
Kx = 0.3 Cosφ = 0.6 tgφ = 1.33 Pjs = 0.3×3 = 0.9 kW
Qjs = Pjs× tgφ=0.9×1.33 = 1.2 kvar
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西苑住宅小区10#、11#楼 专项施工方案
(12)、木工电刨
Kx = 0.3 Cosφ = 0.6 tgφ = 1.33 Pjs = 0.3×0.7 = 0.21 kW
Qjs = Pjs× tgφ=0.21×1.33 = 0.28 kvar (13)、木工平刨床
Kx = 0.3 Cosφ = 0.6 tgφ = 1.33 Pjs = 0.3×3 = 0.9 kW
Qjs = Pjs× tgφ=0.9×1.33 = 1.2 kvar
(14)总的计算负荷计算，总箱同期系数取 Kx = 0.9 总的有功功率 Pjs = Kx×ΣPjs = 0.9×
(9.66+1.1+12.14+0.75+0.24+0.15+12.14+9.66+0.75+0.24+0.15+1.2+2.1+0.9+0.89+0.9+0.21+0.9) = 48.678 kW
总的无功功率 Qjs = Kx×ΣQjs =0.9×
(9.86+1.67+16.19+1.14+0.24+0.15+16.19+9.86+1.14+0.24+0.15+1.22+2.14+0.92+2.04+1.2+0.28+1.2) = 59.258 kvar
总的视在功率
Sjs = ( Pjs+Qjs ) = (48.678+59.258) = 76.688 kVA 总的计算电流计算
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