发布时间 : 2024/5/17 17:37:57 星期五 文章at89c52tlc5615信号发生器(正弦 方波 三角波)更新完毕开始阅读a0ce16d0d8ef5ef7ba0d4a7302768e9951e76ed1

/***************************************************************************//*信号发生器（正弦方波三角波）

*//**************************************************************************/#include

52.h>

#include #define uchar unsigned char #define uint unsigned int sbit cs=P2^0;//tlc5615片选端口 //tlc5615时钟线 //tlc5615传输端口 sbit clk=P2^1; sbit din=P2^2; sbit key1=P1^0; sbit key2=P1^1; uchar keydat;

uchar flag;//按键的单片机接口

//波形发生终止信号的标志位一旦被置零立马停止发信号 uchar flagsqu;//方波高低电平控制为（运用定时器1中断控制） uchar m,num; uchar dat=0xff;

uchar code tosin[141]={//正弦波的编码

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0x00,0x01,0x02,0x02,0x03,0x04,0x05,0x06,0x07,0x08, 0x09,0x0a,0x0b,0x0d,0x0e,0x10,0x11,0x13,0x15,0x16, 0x18,0x1a,0x1c,0x1e,0x20,0x22,0x25,0x27,0x29,0x2b, 0x2e,0x30,0x33,0x35,0x38,0x3a,0x3d,0x40,0x43,0x45, 0x48,0x4c,0x4e,0x51,0x55,0x57,0x5a,0x5d,0x60,0x63, 0x66,0x69,0x6c,0x6f,0x70,0x71,0x72,0x73,0x74,0x75, 0x76,0x77,0x78,0x79,0x7a,0x7b,0x7c,0x7d,0x7e,0x7e, 0x7f,0x80,0x7f,0x7e,0x7e,0x7d,0x7c,0x7b,0x7a,0x79, 0x78,0x77,0x76,0x75,0x74,0x73,0x72,0x6f,0x6c,0x69, 0x66,0x63,0x60,0x5d,0x5a,0x57,0x55,0x51,0x4e,0x4c, 0x48,0x45,0x43,0x40,0x3d,0x3a,0x38,0x35,0x33,0x30, 0x2e,0x2b,0x29,0x27,0x25,0x22,0x20,0x1e,0x1c,0x1a, 0x18,0x16,0x15,0x13,0x11,0x10,0x0e,0x0d,0x0b,0x0a, 0x09,0x08,0x07,0x06,0x05,0x04,0x03,0x02,0x02,0x01, 0x00}; //xx函数

void delay(uchar z){} void prepare(){cs=1; din=1; uchar x,y; for(x=0;x<110;x++)

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for(y=z;y>0;y--); //tlc5615的初始化 clk=0; cs=0;

clk为低时进?}void Squtranslator(){uchar j; uchar dat1=0x7f; while(flag){do{ prepare(); dat=dat1;

for(j=0;j<12;j++){din=(bit)(dat>>7); clk=1; dat=dat<<1; clk=0;}cs=1;

clk为低时进行//cs的上升沿和下降沿必须在//方波函数 //将数据的最高位赋给din//一位位的传输 //cs的上升沿和下降沿必须在delay (200); if(dat1==0) dat1=0x7f;换else dat1=0; }while(flag);}}

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void Tratranslator(){uchar j; uchar dat1=0x7f; while(flag){do{ prepare(); dat=dat1;

for(j=0;j<12;j++){din=(bit)(dat>>7);

clk=1;//使高低电平持续一段时间//完成了0和0x7f之间的替//锯齿波的发生函数

//将数据的最高位赋给dindat=dat<<1; clk=0;}cs=1; clk为低时进行 delay (2); dat1--;

}while(flag && dat1); 停止 do{ prepare(); dat=dat1;

for(j=0;j<12;j++){din=(bit)(dat>>7); clk=1; dat=dat<<1;

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