电力系统分析练习题及其答案2 联系客服

发布时间 : 星期一 文章电力系统分析练习题及其答案2更新完毕开始阅读a528b49576eeaeaad0f3301e

[例2-1]一条220kV的输电线,长180km,导线为LGJ-400(直径2.8cm),水平排列,相间距7m,求该线路的R,X,B,并画等值电路. 解: 电阻:r1??S?31.5?0.08?/km R?r1l?0.08?180?14.4? 400电抗:Deq?3700?700?2?700?882cm x1?0.1445lgDeq0.8r?0.1445lg882?0.42?/km

0.8?1.4 X?x1?l?0.42?180?75.6? 电纳:b1?7.587.58?10?6??10?6?2.7?10?6S/km Deq882lglg1.4rB?b1l?2.7?10?6?180?486?10?6S

等值电路:

[例2-2]220kV架空线,水平排列,相间距7m,每相为2?LGJQ?240分裂导线,计算直径21.88mm,分裂间距400mm,求每相单位长度的电阻、电抗和电纳。 解: 电阻:r1??S?31.5=0.066?/km 2?24021.88?400?62.757 21

电抗:Dsb?Dsd?0.9?

Deq?37000?7000?2?7000?8820mm

x1?0.1445lg电纳:req?rd?b1?DeqDsb?0.1445lg8820?0.31?/km 62.75721.88?400?66.151 27.587.58?10?6??10?6?3.567?10?6S/km Deq8820lglg66.151req[例2-3]一长度为600 km 的500kV 架空线路,使用4×LGJQ-400 四分裂导线,r1?0.0187?km,x1?0.275?km,b1?4.05?10?6Skm,g1?0。试计算该线路的?形等值电路参数。 解 (1)精确计算。

z?r?jx?(0.0187?j0.275)?km?0.2756?(86.11?km)y?jb?4.05?10?6?90Skm?l?zyl?6000.2756?4.05?10?6?(83.11?90)2?0.6339?88.06?0.02146?j0.6335sh(?l)?0.5(e?l?e??l)?0.0173?j0.5922?0.5924?88.33KZ?sh?l0.5924?88.33??0.9345?0.27?l0.6339?88.062(ch?l?1)0.3886?176.32??1.035??1.07?lsh(?l)0.3755?176.39

ch(?l)?0.5(e?l?e??l)?0.8061?j0.0127KY?计算?形等效电路参数:

Z??KZzl?0.9345?0.27?0.2756?86.11?600??154.53?86038? Y?2?KY(jb2)l?1.035??0.07?4.05?10?6?90?300S

?1.258?10?3?89.93S?j1.258?10?3S(2)使用近似算法计算。

2

11xbl2?1??0.275?4.05?6002?10?6?0.866331r22kx?1?b(x?)l?0.9336x12k?1?xbl?1.033b 12Z?krrl?jkxl?(9.72?j153.9)?kr?1?Y2?j4.05?10?6?300?1.033S?j1.255?10?3S 与准确计算相比,电阻误差-0.4%,电抗误差-0.12%,电纳误差-0.24%,本例线路长度小于1000km ,用实用近似公式计算已能够满足精确要求。 如果直接取

KZ?KY?1,则Z=(r1+jx1)l?(11.22?j165)?

这时,电阻误差达15%,电抗误差7%,电纳误差-3.4%,误差已较大。 例

02-4 330kV

0架空线路的参数为

0r?0.0579?/km,x?0.316?/km,g?0,b0?3.5?10?6s/km.试分别计算长度为

100,200,300,400和500线路的π型等值参数的近视值,修正值和精确值。

解 首先计算100km线路的参数

(一)Z?`?(r0?jx0)l?(0.0579?j0.316)?100??(5.79?j31.6)?

Y??(g`0?jb0)l?(0?j3.55?10?6)?100s?j3.55?10?4s

(二) 修正参数计算

kr?1?13xbl002?1?1?0.316?3.55?10?6?1002?0.9963 32b112?62?620?1??)l?1?[0.316?3.55?10?0.0579?3.55?10/0.316]?100(xkxbr00066x0?0.99823

kb?1?`112r0xbl002?1?1?0.316?3.55?10?6?1002?1.0009 12Z??(kr`b?jkxx0)l?(0.9963?0.0579?j0.9982?0.316)?100??(5.7686?j31.5431)?0Y??jkbl?Zj1.0009?3.55?10?6?100s?3.5533?10?4s

(三) 精确参数计算

c?(r0?jx0)/(g?jb0)?(0.0579?j0.316)/(j3.55?10?6)0?(299.5914?j27.2201)??300.8255??5.1920?

??(r0?jx0)(g?jb0)?(0.0579?j0.316)(j3.55?10?6)0?(0.9663?j0.6355)?10?4km?1

?l?(0.9663?j10.63555)?10?4?100?(0.9663?j0.6355)?10?2

计算双曲线函数。 利用公式

sh(x+jy)=shxcosy+jchxsiny ch(x+jy)=chxcosy+jshxsiny 将之值代入,便得

sh?l?sh(0.9633?10?2?j10.6355?10?2)?sh(0.9633?10?2)cos(10.6355?10?2)?jch(0.9633?10?2)sin(10.6355?10?2)?(0.9609?j10.6160)?10?2ch?l?ch(0.9633?10?2?j10.6355?10?2)?sh(0.9633?10?2)cos(10.6355?10?2)?jsh(0.9633?10?2)sin(10.6355?10?2)?0.9944?j0.1026?10?2?l

II型电路的精确参数为

4