·¢²¼Ê±¼ä : ÐÇÆÚÁù ÎÄÕÂTX-10ÓÐЧ³É·Öº¬Á¿¸üÐÂÍê±Ï¿ªÊ¼ÔĶÁc315aa46be1e650e52ea991b
ÈÉ»ù·Ó¾ÛÑõÒÒÏ©ÃÑ(È黯¼ÁNP-10)ÓÐЧ³É·ÖµÄ²â¶¨
?
ËùÊôÀà±ð£º
³£ÓñíÃæ»î¼ÁÆÊÎö
?
?
¡¾Õª Òª¡¿
ÓÃÒѺãÁ¿(ºãÁ¿Îó²î¡À0.0003g)Èý±âÐγÆÁ¿Æ¿(Éù70mm¡Á
35mm)£¬³ÆÈ¡ÊÔÑù10g(³Æ×¼ÖÁ0.O01g)£¬ÖÃÓÚºæÏäÖУ¬ÔÚζÈ(100¡«105)¡æÖкæ4hºó£¬È¡³öÖÃÓÚ¸ÉÔïÆ÷ÖУ¬ÀäÖÁÊÒΣ¬Ñ¸ËÙ³ÆÁ¿£¬ÓÐЧ³É·Öº¬Á¿µÄÖÊÁ¿·ÖÊýX°´Ê½(1)¼ÆËã
(1)
ʽÖÐ m¡ª¡ªÊÔÑùµÄÖÊÁ¿£¬g£»
m1¡ª¡ªºæºó³ÆÁ¿Æ¿Á¬Í¬ÊÔÑùµÄÖÊÁ¿£¬g£» m2¡ª¡ªºæÇ°³ÆÁ¿Æ¿Á¬Í¬ÊÔÑùµÄÖÊÁ¿£¬g.
ƽÐвⶨÁ½´Î£¬È¡ÆäËãÊõƽ¾ùֵΪ²â¶¨½á¹û£¬Æ½Ðвⶨ½á¹ûÖ®²î²»´óÓÚƽ¾ùÖµµÄ5£¥¡£
×¢£º
±¾·½·¨²ÎÕÕ±ê×¼HG£¯T 2563¡ª1994£¬ÊÊÓÃÓÚÈÉ»ù·ÓÓë10mol»·Ñõ
ÒÒÍéËõºÏ¶ø³ÉµÄÍé»ù·Ó¾ÛÑõÒÒÏ©ÃÑ(¼ò³ÆÈ黯¼ÁNP-10»òTX-10)¡£Ö÷
ÒªÓÃÓÚ·ÄÖ¯¡¢Ê¯ÓÍ¡¢»¯¹¤¡¢Ï𽺡¢»úе¡¢Æ¤¸ïµÈ¹¤Òµ£¬ÓÉÓÚ´æÔÚ×ÅÉúÎï½µ½âÎÊÌ⣬Òѱ»½ûÓÃÓÚÏ´µÓ¼ÁÖС£ ½á¹¹Ê½
ÈÉ»ù·Ó¾ÛÑõÒÒÏ©ÃÑ(È黯¼ÁNP-10)¡ªÉ«¶È²â¶¨
?
ËùÊôÀà±ð£º
³£ÓñíÃæ»î¼ÁÆÊÎö
?
?
¡¾Õª Òª¡¿
°´ÕÕ±ê×¼GB 9282¡ª1988¹æ¶¨½øÐС£²â¶¨·½·¨ÈçÏ£º
°´GB 9282¡ª1988µÄ¹æ¶¨²â¶¨£¬n¡Ü9µÄÑùÆ·ÓÃÔÑù²â¶¨£¬ÈçÑùÆ·ÔÚÊÒÎÂÏÂΪ¸àÌå»ò¹ÌÌ壬¿É¼ÓÈÈÖÁ¸ÕºÃÈÛÈÚºó²â¶¨£»n>9µÄÑùÆ·£¬ÅäÖƳÉ100g/LµÄ95£¥ÒÒ´¼ÈÜÒº²â¶¨¡£GB 9282¡ª1988¹æ¶¨ÁËÓò¬Ò»îܵ¥Î»À´ÆÀ¶¨Í¸Ã÷ÒºÌåÑÕÉ«µÄ·½·¨¡£²¬îܵ¥Î»ÊÇ1LÈÜÒºÖк¬lmg²¬(ÒÔÂȲ¬ËáÑÎÀë×ÓÐÎʽ´æÔÚ)¼°2mgÂÈ»¯îÜ(¢ò)ÁùË®ºÏÎïʱµÄÈÜÒºÑÕÉ«¡£±¾±ê×¼ÊÊÓÃÓÚÑÕÉ«ºÍ²¬Ò»îܵȼ¶±ê×¼ÑÕÉ«ÏàËƵÄ͸Ã÷ÒºÌå¡£
(Ò»)·½·¨¸ÅÊö
½«ÑùÆ·µÄÑÕÉ«ÓëÑÕÉ«±ê×¼½øÐбȽϣ¬²¢Óò¬Ò»îÜÑÕÉ«µ¥Î»À´±íʾ½á¹û¡£ (¶þ)ÒÇÆ÷ºÍÊÔ¼Á
(1)·Ö¹â¹â¶È¼Æ Äܲⶨ²¨³¤Îª430nm?455nm?480nmºÍ510nmµÄ¹â͸ÉäÂÊ?¹â¶È¼Æ͸ÉäÂʵľ«È·¶ÈӦΪ0.005»ò¸ü¾«È·Ð©?
(2)±ÈÉ«³Ø ¹â³ÌΪl0mm³¤?
(3)±ÈÉ«¼Æ Æä½á¹¹Ê¹¹âÏßÑرÈÉ«¹ÜµÄ×ÝÖá·½Ïò͸¹ý,ÒÔ±ãÓÃÊÓÁ¦½øÐбȽÏ?ʹ´Ó°×É«²£Á§°å͸Éä¹ýÀ´»ò·´Éä³öÈ¥µÄ°×É«¹âÏßÒÔÏàµÈµÄÇ¿¶È´©Í¸±ÈÉ«¹Ü?±ÈÉ«¼ÆµÄÁ½¶ËÓ¦Óе²°å,·ÀÖ¹¹âÏß´Ó²àÃæ͸½ø±ÈÉ«¹Ü?
(4)±ÈÉ«¹Ü ÓÖͨ³ÆÄÉÊϹÜ(Nessler¹Ü),ƽµ×,ÈÝÁ¿Îª100ml,ÓÐÄ¥¿Ú͸Ã÷µÄ²£Á§Èû?¸÷±ÈÉ«¹Ü²£Á§µÄÑÕÉ«Ó¦Ò»ÖÂ,¹Üµ×ÒÔÉÏ275mmºÍ295mmÖ®¼äÓ¦±êÓп̶ÈÏß,²¢Ê¹¸÷±ÈÉ«¹Ü¿Ì¶ÈÏßÖ®¸ß¶ÈÏà²î²»³¬¹ý3mm?
(5)ÂȲ¬Ëá¼Ø(K2PtCl6)?
(6)ÂÈ»¯îÜ(¢ò)(COCl2¡¤6H20)(GB1270)?
(7)ÕôÁóË®(H20)(GB 6682) ¶þ¼¶? (8)ÑÎËá(HCl)(GB 622)?
(Èý)²Ù×÷²½Öè
1.ÑÕÉ«±ê×¼µÄÖƱ¸ (1)ÅäÖÆ
¢ÙÑÕÉ«ÔÒº(²¬-îܵ¥Î»Îª500) ³ÆÈ¡1.245gÂȲ¬Ëá¼ØºÍ1.000g
ÂÈ»¯îÜ(¢ò)£¬·ÅÈë400mlÉÕ±ÖУ¬ÓÃÉÙÁ¿ÕôÁóˮʪÈóºó£¬¼ÓÈël00mlÑÎËᣬ¿É¼ÓÎÂʹÆäÈܽ⣬ÒԵõ½Í¸Ã÷ÈÜÒº¡£´ýÈÜÒºÀäÈ´ºó£¬ÒÆÖÁ1000mlÈÝÁ¿Æ¿ÖУ¬ÓÃÕôÁóˮϡÊÍÖÁ¿Ì¶È£¬Ò¡ÔÈ¡£
½«ÒÔÉÏÑÕÉ«ÔÒº·ÅÈë±ÈÉ«³ØÖÐÓ÷ֹâ¹â¶È¼Æ½øÐвⶨ£¬ÈçÆä͸Éä
ÂÊ·ûºÏ±í1ÖÐËù¹æ¶¨µÄ͸ÉäÂÊ·¶Î§£¬³Æ¸ÃÈÜÒº¾ßÓв¬Ò»îܵ¥Î»Îª500µÄÑÕÉ«ÔÒº¡£
±í1 ²¬-îܵ¥Î»Îª500ʱ£¬²¬-îÜÔҺ͸ÉäÂÊÓëÎü¹â¶ÈµÄÔÊÐí·¶Î§
²¨³¤£¯nm ͸ÉäÂÊ Îü¹â¶È 430 0.759¡«0.776 0.110¡«O.120 455 0.716¡«0.741 0.130¡«0.I45 480 0.759¡«0.785 0.105¡«O.120 510 0.861¡ª0.881 0.O55¡«0.O65
¢Ú²¬-îܱê×¼±ÈÉ«ÈÜÒº °´±í2ÖÐËùÁеÄÒªÇó·¶Î§£¬Á¿È¡²¬-îÜÔ
Òº·ÅÈë±ÈÉ«¹ÜÖУ¬ÓÃÕôÁóˮϡÊ͵½100ml£¬²¢Ò¡ÔÈ¡£È»ºó½«±ÈÉ«¹Ü¸ÇÉϸÇ×Ó£¬Óó潺Æá»òʯÀ¯ÓëËÉÏã»ìºÏÒº½øÐÐÃܷ⣬²¢·Ö±ðÔÚ±ÈÉ«¹ÜÉϱêÃ÷²¬Ò»îܵ¥Î»¡£
±í2²¬-îܱê×¼±ÈÉ«ÈÜÒº ÑÕÉ«£¯ÑÕÉ«ÔÒº ÑÕÉ«£¯²¬ÑÕÉ«ÔÑÕÉ«£¯²¬-²¬-îܵÄÌå»ý£¯-îܵ¥Î» Òº îܵ¥Î» µ¥Î» ml µÄÌå»ý £¯ml 0 0 50 10 200 5 1 60 12 250 10 2 70 14 300 15 3 80 16 350 20 4 90 18 400 25 5 100 20 450 30 6 125 25 500 35 7 150 30 40 8 175 35
(2)´¢´æ½«ÃÜ·âºÃµÄÑÕÉ«ÔÒº´æ·ÅÓÚºÚ°µ´¦£¬ÆäÑÕÉ«¿ÉÎȶ¨lÄê¡£È罫²¬.îܱê×¼±ÈÉ«Òº´æ·ÅÔÚºÚ°µ´¦¿ÉÎȶ¨°ëÄ꣬µ«×îºÃʹÓøÕÅäÖƺõÄÈÜÒº¡£
2.²â¶¨
½«ÑùÆ·µ¹Èë1Ö§100ml±ÈÉ«¹ÜÖÐÖÁ¿Ì¶ÈÏß´¦¡£ÈçÑùÆ·Óлë×ÇÏÖÏó»òÓпɼûÔÓÖʵĻ°£¬Ó¦ÏÈÐйýÂË£¬ÒԵõ½Í¸Ã÷µÄÈÜÒº¡£È»ºó¸ÇÉϸÇ×Óºó·ÅÔÚ±ÈÉ«¼ÆÉÏ£¬ÓÃÊÓÁ¦¹Û²ìÓë±ê×¼±ÈÉ«ÈÜÒº½øÐбȽϣ¬Ê¹ÆäÑÕÉ«´ïµ½×î½Ó½üµÄij²¬Ò»×ê±ê×¼±ÈÉ«ÈÜҺΪֹ¡£ (ËÄ)½á¹û
1.ÑùÆ·µÄÑÕÉ«ÒÔ×î½Ó½üÑùÆ·ÑÕÉ«µÄijһ±ê×¼±ÈÉ«ÈÜÒºµÄ²¬.îܵ¥Î»ÊýÀ´±íʾ£¬Èç¹ûÑÕÉ«½éÓÚÁ½±ê×¼±ÈÉ«ÈÜÒºÖ®¼ä£¬ÔòÒÔÆäÖÐÑÕÉ«ÉîÕßµÄÊýÄ¿À´±íʾ¡£
2.Èç¹ûÑùÆ·µÄÑÕÉ«ÌØÐÔÓë±ê×¼±ÈÉ«ÈÜÒº²»Í¬£¬´Ó¶ø²»ÄܽøÐÐÈ·ÇжԱÈʱ£¬°´1Ìõ¼Ç¼ÏÂÄܵõ½½üËƵȼ¶µÄÑÕÉ«µ¥Î»£¬²¢¶Ô¹Û²ìµ½µÄÑÕÉ«×÷һ˵Ã÷£¬»ò¼Ç¼Ϊ¡°É«Ï಻ͬ¡±¡£Í¬Ò»²Ù×÷ÕßÔÚͬһ¸öʵÑéÊÒ¼°¶Ìʱ¼ä¼ä¸ôÄÚ£¬Ê¹ÓÃͬÑùµÄÒÇÆ÷¼°±ê×¼µÄÊÔÑé·½·¨£¬ÔÚÖÃÐŶÈΪ95£¥Ê±£¬¶ÔͬһÖÖÊÔÑùËù²âµÃµÄÁ½¸öµ¥´ÎÊÔÑé½á¹û¼äµÄ¾ø¶Ô²îӦСÓÚ5.1£¥¡£²»Í¬µÄ²Ù×÷ÕßÔÚ²»Í¬µÄʵÑéÊÒÄÚ£¬Ê¹Óñê×¼µÄÊÔÑé·½
ÑÕÉ«ÔÒº µÄÌå»ý£¯ml 40 50 60 70 80 90 100
·¨£¬ÔÚÖÃÐŶÈΪ95£¥Ê±£¬¶ÔͬһÖÖÊÔÑùËù²âµÃµÄÁ½¸öµ¥ÏîÊÔÑé½á¹ûµÄ¾ø¶Ô²îӦСÓÚ17£¥¡£ (Îå)ÊÔÑ鱨¸æ
ÊÔÑ鱨¸æÓ¦°üÀ¨ÏÂÁÐÄÚÈÝ£º ÊÔÑé²úÆ·µÄÀàÐͺÍÃû³Æ£» ×¢Ã÷ʹÓõÄÊÔÑé·½·¨£» ²âÊÔʱעÒâµ½µÄÒì³£ÏÖÏó£»
ÊÔÑé½á¹û£¬ÒÔ²¬Ò»îÜÑÕÉ«µ¥Î»Êý±íʾ¡£Èç½á¹ûÊÇÑùÆ·¾¹ýÂ˺ó²âµÃµÄ£¬ÔòӦעÃ÷£»
ÊÔÑéÈÕÆÚ¡£ ×¢£º
±¾·½·¨²ÎÕÕ±ê×¼HG£¯T 2563¡ª1994£¬ÊÊÓÃÓÚÈÉ»ù·ÓÓë10mol»·Ñõ
ÒÒÍéËõºÏ¶ø³ÉµÄÍé»ù·Ó¾ÛÑõÒÒÏ©ÃÑ(¼ò³ÆÈ黯¼ÁNP-10»òTX-10)¡£Ö÷
ÒªÓÃÓÚ·ÄÖ¯¡¢Ê¯ÓÍ¡¢»¯¹¤¡¢Ï𽺡¢»úе¡¢Æ¤¸ïµÈ¹¤Òµ£¬ÓÉÓÚ´æÔÚ×ÅÉúÎï½µ½âÎÊÌ⣬Òѱ»½ûÓÃÓÚÏ´µÓ¼ÁÖС£ ½á¹¹Ê½
ÈÉ»ù·Ó¾ÛÑõÒÒÏ©ÃÑ(È黯¼ÁNP-10)¡ªÍâ¹ÛµÄ²â¶¨
?
ËùÊôÀà±ð£º
³£ÓñíÃæ»î¼ÁÆÊÎö
?
?
¡¾Õª Òª¡¿
ÔÚÊÒÎÂϽ«ÊÔÑùµ¹Èë50ml±ÈÉ«¹ÜÖнøÐÐÄ¿²âÆÀ¶¨¡£
×¢£º
±¾·½·¨²ÎÕÕ±ê×¼HG£¯T 2563¡ª1994£¬ÊÊÓÃÓÚÈÉ»ù·ÓÓë10mol»·Ñõ
ÒÒÍéËõºÏ¶ø³ÉµÄÍé»ù·Ó¾ÛÑõÒÒÏ©ÃÑ(¼ò³ÆÈ黯¼ÁNP-10»òTX-10)¡£Ö÷
ÒªÓÃÓÚ·ÄÖ¯¡¢Ê¯ÓÍ¡¢»¯¹¤¡¢Ï𽺡¢»úе¡¢Æ¤¸ïµÈ¹¤Òµ£¬ÓÉÓÚ´æÔÚ×ÅÉúÎï½µ½âÎÊÌ⣬Òѱ»½ûÓÃÓÚÏ´µÓ¼ÁÖС£ ½á¹¹Ê½
ÈÉ»ù·Ó¾ÛÑõÒÒÏ©ÃÑ(È黯¼ÁNP-10)¡ªpHÖµµÄ²â¶¨
?
ËùÊôÀà±ð£º