发布时间 : 2024/6/18 19:34:08 星期二 文章潭浩强C语言第三版答案更新完毕开始阅读c848c90ef12d2af90242e6b2

main()

{int N1=100,N2=50,N3=10; float k;

float s1=0,s2=0,s3=0; for(k=1;k<=N1;k++)s1+=k; for(k=1;k<=N2;k++)s2+=k*k; for(k=1;k<=N3;k++)s3+=1/k; printf(\} 5.6 main() {int i,j,k,n;

for(n=100;n<1000;n++) {i=n/100; j=n/10-i*10; k=n;

if(i*100+j*10+k==i*i*i+j*j*j+k*k*k) printf(\ } } 5.7

#define M 1000 main()

{int k0,k1,k2,k3,k4,k5,k6,k7,k8,k9; int i,j,n,s; for(j=2;j<=M;j++) {n=0; s=j;

for(i=1;i

{case 1:k0=i;break; case 2:k1=i;break; case 3:k2=i;break; case 4:k3=i;break; case 5:k4=i;break; case 6:k5=i;break; case 7:k6=i;break; case 8:k7=i;break; case 9:k8=i;break;

case 10:k9=i;break; } } } if(s==0)

{printf(\

if(n>1)printf(\ if(n>2)printf(\ if(n>3)printf(\ if(n>4)printf(\ if(n>5)printf(\ if(n>6)printf(\ if(n>7)printf(\ if(n>8)printf(\ if(n>9)printf(\ } } } main() {static int k[10]; int i,j,n,s;

for(j=2;j<=1000;j++) {n=-1; s=j;

for(i=1;i

{printf(\ for(i=0;i

{int n,t,number=20;

float a=2;b=1;s=0; for(n=1;n<=number;n++) {s=s+a/b; t=a,a=a+b,b=t; }

printf(\} 5.9 main()

{float sn=100.0,hn=sn/2; int n;

for(n=2;n<=10;n++) {sn=sn+2*hn; hn=hn/2; }

printf(\printf(\} 5.10 main() {int day,x1,x2; day=9; x2=1; while(day>0) {x1=(x2+1)*2; x2=x1; day--; }

printf(\} 5.11

#include\main()

{float a,xn0,xn1; scanf(\xn0=a/2;

xn1=(xn0+a/xn0)/2; do {xn0=xn1; xn1=(xn0+a/xn0)/2; }

while(fabs(xn0-xn1)>=1e-5);

printf(\} 5.12

#include\main() {float x,x0,f,f1; x=1.5; do {x0=x;

f=((2*x0-4)*x0+3)*x0-6; f1=(6*x0-8)*x0+3; x=x0-f/f1; }

while(fabs(x-x0)>=1e-5); printf(\} 5.13

#include\main()

{float x0,x1,x2,fx0,fx1,fx2; do

{scanf(\ fx1=x1*((2*x1-4)*x1+3)-6; fx2=x2*((2*x2-4)*x2+3)-6; }

while(fx1*fx2>0); do

{x0=(x1+x2)/2;

fx0=x0*((2*x0-4)*x0+3)-6; if((fx0*fx1)<0) {x2=x0; fx2=fx0; } else {x1=x0; fx1=fx0; } }

while(fabs(fx0)>=1e-5); printf(\}