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1. EDTA¶þÄÆÑεÄË®ÈÜÒºµÄpHµÄ×î¼òʽÊÇ£¨pH = (pKa4 + pKa5) /2£© (EDTAÏ൱ÓÚÁùÔªËá)

2. ÂçºÏµÎ¶¨ÖÐÒ»°ã²»Ê¹ÓÃEDTA¶øÓÃEDTA¶þÄÆÑÎ(Na2H2Y), ÕâÊÇÓÉÓÚ£¨EDTAÔÚË®ÖеÄÈܽâ¶ÈС, ¶øNa2H2YµÄÈܽâ¶È½Ï´ó£©; µ±ÔÚÇ¿ËáÐÔÈÜÒºÖÐ(pH<1), EDTAΪÁùÔªËá, ÕâÊÇÒòΪ£¨Á½¸öNÔ­×Ó½ÓÊÜÁËÁ½¸öÖÊ×Ó£©¡£ 3£®Ö±½ÓÓë½ðÊôÀë×ÓÅäλµÄEDTAÐÍÌåΪ£¨D £© £¨A£©H6Y2+ £¨B£©H4Y £¨C£©H2Y2£­ £¨D£©Y4£­ 4. Ö¸³öÏÂÁÐEDTAÂçºÏÎïµÄÑÕÉ«(Ìî A,B,C,D) (1) CuY2- ___ D _____ £¨A£© ÎÞÉ«

2- (2) MnY __ B ______ £¨B£© ×ϺìÉ« (3) FeY- ___C _____ £¨C£© »ÆÉ« (4) ZnY2- ___ A ____ £¨D£© À¶É«

5£®Ò»°ãÇé¿öÏ£¬EDTAÓë½ðÊôÀë×ÓÐγɵÄÂçºÏÎïµÄÂçºÏ±ÈÊÇ£¨A £© £¨A£©1£º1 £¨B£©2£º1 £¨C£©1£º3 £¨D£©1£º2

6. ½ðÊôÀë×ÓMÓëÂçºÏ¼ÁLÐγÉÖð¼¶ÂçºÏÎï, ÈÜÒºÖи÷ÖÖ´æÔÚÐÍÌåµÄ·Ö²¼ÏµÊýÓëÂçºÏ¼ÁµÄƽºâŨ¶È£¨Óйأ©; Óë½ðÊôÀë×ÓµÄ×ÜŨ¶È£¨Î޹أ©¡£(´ðÓйػòÎÞ¹Ø) 7. ÒÑÖªÒÒõ£±ûͪ(L)ÓëAl3+ÂçºÏÎïµÄlg?1-lg?3·Ö±ðÊÇ8.6¡¢15.5ºÍ21.3, ÔòAlL3ΪÖ÷ÒªÐÎʽʱµÄpL·¶Î§ÊÇ£¨pL < 5.8£©£¬pLΪ10.0ʱÂÁµÄÖ÷ÒªÐÎʽÊÇ£¨Al3+£©£¬Ôò[AlL]Óë[AlL2]ÏàµÈʱµÄpLֵΪ£¨6.9£©

8. »Ç»ùË®ÑîËá(L)ÓëCu2+ÂçºÏÎïµÄlg?1Ϊ9.5, lg?2Ϊ16.5, [CuL]´ï×î´óµÄpLΪ ( D )

(A) 9.5 (B) 16.5 (C) 7.0 (D) 8.3 9£®¦ÁM(L)=1±íʾ£¨ A £©

£¨A£©MÓëLûÓи±·´Ó¦ £¨B£©MÓëLµÄ¸±·´Ó¦Ï൱ÑÏÖØ £¨C£©MµÄ¸±·´Ó¦½ÏС £¨D£©[M]=[L] 10. ÈôÂçºÏµÎ¶¨·´Ó¦Îª

M + Y = MY L©¦ ©¦H+

ML HiY(i=1~6)

ÔòËáЧӦϵÊý?Y(H)µÄ¶¨ÒåʽΪ£¨?Y(H)=[Y']/[Y]£©£¬[Y']=£¨[Y']=[Y]+¡Æ[HiY]£© c(Y)=£¨[Y]+¡Æ[HiY]+[MY]»òc(Y)=[Y']+[MY]£©¡£ ÂçºÏЧӦϵÊý?M(L)µÄ¶¨ÒåʽΪ£¨?M(L)=[M']/[M]£©¡£

11. ÈôEDTAµÎ¶¨M·´Ó¦Îª M+Y=MY ¡ýA MA

ÒÔϱíʾÕýÈ·µÄÊÇ ( A )

(A) c(M)=[M']+[MY] (B) c(M)=[M]+[M']+[MY] (C) c(M)=[MA]+[MY] (D) c(M)=[M]+[MA]

12. ÓÃEDTAµÎ¶¨½ðÊôM, ÈôM·Ö±ðÓëA,B,CÈýÕß·¢Éú¸±·´Ó¦,´Ëʱ¼ÆËã?MµÄ¹«Ê½ÊÇ?M = £¨?M(A)+?M(B)+?M(C)-2 £©¡£

13. ÔÚÒ»¶¨Ëá¶ÈÏÂ, ÓÃEDTAµÎ¶¨½ðÊôÀë×ÓM¡£µ±ÈÜÒºÖдæÔÚ¸ÉÈÅÀë×ÓNʱ, Ó°

ÏìÂçºÏ¼Á×ܸ±·´Ó¦ÏµÊý´óСµÄÒòËØÊÇ ( C ) (A) ËáЧӦϵÊý?Y(H)

(B) ¹²´æÀë×Ó¸±·´Ó¦ÏµÊý?Y(N)

(C) ËáЧӦϵÊý?Y(H)ºÍ¹²´æÀë×Ó¸±·´Ó¦ÏµÊý?Y(N) (D) ÂçºÏÎïÎȶ¨³£ÊýK(MY)ºÍK(NY)Ö®±ÈÖµ 14. Ö¸³öÏÂÁÐÐðÊöÖдíÎóµÄ½áÂÛ ( D )

(A) ÂçºÏ¼ÁµÄËáЧӦʹÂçºÏÎïµÄÎȶ¨ÐÔ½µµÍ (B) ½ðÊôÀë×ÓµÄË®½âЧӦʹÂçºÏÎïµÄÎȶ¨ÐÔ½µµÍ (C) ¸¨ÖúÂçºÏЧӦʹÂçºÏÎïµÄÎȶ¨ÐÔ½µµÍ (D) ¸÷ÖÖ¸±·´Ó¦¾ùʹÂçºÏÎïµÄÎȶ¨ÐÔ½µµÍ

15. ÔÚpHΪ10.0µÄ°±ÐÔÈÜÒºÖÐ, ÒѼÆËã³ö?Zn(NH3)=104.7, ?Zn(OH)=102.4, ?Y(H)=100.5¡£ÔòÔÚ´ËÌõ¼þÏÂlgK'(ZnY)Ϊ ( D ) [ÒÑÖª lgK(ZnY)=16.5]

(A) 8.9 (B) 11.8 (C) 14.3 (D) 11.3

16. ´Ëͼ±íʾ¸÷ÖÖ¸±·´Ó¦¶ÔAl-EDTAÂçºÏÎïÎȶ¨ÐÔµÄÓ°Ïì, ÆäÖи÷ÇúÏß·Ö±ð´ú±í: (ÌîA,B,C,D)

(1) ÇúÏߢñ_ A ___ (2) ÇúÏߢò_ C ___ (3) ÇúÏߢó__ B __ (4) ÇúÏߢô_ D __

£¨A£© lgK(AlY) £¨B£© lgK(Al'Y') £¨C£© lgK(AlY') £¨D£© lgK[Al'Y',(AlY)']

2+

17. ½ñÓÐÁ½·ÝÏàͬŨ¶ÈµÄZnÈÜÒº£¬·Ö±ðΪpH = 10.0µÄ°±ÐÔ»º³åÈÜÒººÍpH = 5.5µÄÁù´Î¼×»ùËÄ°·»º³åÈÜÒº¡£¶ÔpZnÖµµÄ´óСÐðÊöÕýÈ·µÄÊÇ¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­ ( B )

( A ) pZnÖµÏàµÈ ( B ) Ç°ÕßµÄpZnÖµ´óÓÚºóÕßµÄpZnÖµ ( C )Ç°ÕßµÄpZnֵСÓÚºóÕßµÄpZnÖµ ( D )ÉÏÊöÈýÖÖÇé¿ö¾ù²»ÕýÈ· 18. ÔÚpH=10µÄ°±ÐÔ»º³åÒºÖÐÓÃEDTAµÎ¶¨Zn2+ÖÁ50%´¦Ê± ( C ) (A) pZn'ÖµÖ»Óë[NH3]ÓÐ¹Ø (B) pZn'ÖµÖ»ÓëlgK'ÓйØ

(C) pZn'ÖµÖ»Óëc(Zn)ÓÐ¹Ø (D) pZn'ÖµÓëÒÔÉÏÈýÕß¾ùÓйØ

19. ÔÚpH = 5.5µÄÁù´Î¼×»ùËÄ°·»º³åÈÜÒºÖУ¬ÓÃEDTAµÎ¶¨Zn2+ÖÁ»¯Ñ§¼ÆÁ¿µãʱ£¬ÒÔϹØϵÕýÈ·µÄÊÇ(B )

( A ) [ Zn2+ ] = [ Y4- ] ( B ) [ Zn2+ ] = [ Y¡ä] ( C ) [ Y4- ] = [ ZnY ] / K¡ä(ZnY) ( D ) c(Y) = [ MY ]

20. ÔÚpH=5.0µÄ´×ËỺ³åÒºÖÐÓÃ0.002 mol/LµÄ EDTA µÎ¶¨Í¬Å¨¶ÈµÄPb2+¡£ÒÑÖª: lgK(PbY)=18.0, lg?Y(H)=6.6, lg?Pb(Ac)=2.0, »¯Ñ§¼ÆÁ¿µãʱÈÜÒºÖÐpPb'ӦΪ ( B )

(A) 8.2 (B) 6.2 (C) 5.2 (D) 3.2

21. ÔÚpH=10µÄ°±ÐÔ»º³åÒºÖÐÒÔEDTAµÎ¶¨Zn2+ÖÁ150%´¦Ê± (B ) (A) pZn'Ö»¾ö¶¨ÓÚlgK(ZnY) (B) pZn'Ö»¾ö¶¨ÓÚlgK'(ZnY) (C) pZn'Ö»¾ö¶¨ÓÚc(Y) (D) pZn'ÓëlgK'(ZnY)¡¢c(Y)¾ùÓÐ¹Ø 22. ÔÚº¬ÓÐNH3-NH4ClµÄpH=10.0µÄ½éÖÊÖÐ, ÒÔ0.0200 mol/L EDTA ÈÜÒºµÎ¶¨20.0 mL 0.0200 mol/L Zn2+ÈÜÒº, µ±¼ÓÈë40.0 mL EDTAÈÜҺʱ, ÔÚÏÂÁÐÐðÊöÖÐ, ÕýÈ·µÄÊÇ ( A )

(A) pZn'=lgK'(ZnY) (B) lg[Zn']=lgKZnY (C) lg[Zn']=lgK'(ZnY) (D) ¶¼²»ÕýÈ·

23. ÒÔEDTAÈÜÒºµÎ¶¨Í¬Å¨¶ÈµÄij½ðÊôÀë×Ó, Èô±£³ÖÆäËüÌõ¼þ²»±ä, ½ö½«EDTAºÍ½ðÊôÀë×ÓŨ¶ÈÔö´ó10±¶, ÔòÁ½Öֵζ¨ÖÐpMÖµÏàͬʱËùÏàÓ¦µÄµÎ¶¨·ÖÊýÊÇ ( D )

(A) 0% (B) 50% (C) 100% (D) 150% 24. º¬ÓÐͬŨ¶ÈµÄMg2+ÈÜÒºA¡¢BÁ½·Ý¡£AÈÜÒºµÄpH = 10.0£¬ÆäÖÐÓÎÀë°±µÄŨ¶ÈΪ0.1 mol /L£»BÈÜÒºµÄpH = 9.5£¬ÆäÖÐÓÎÀë°±µÄŨ¶ÈΪ0.02 mol / L¡£½ñÒÔµÈŨ¶ÈµÄEDTAÈÜÒºµÎ¶¨ÉÏÊöÈÜÒºÖÁ»¯Ñ§¼ÆÁ¿µãʱ¡£¶ÔpY?¼Æ µÄ´óСÐðÊöÕýÈ·µÄÊÇ (B )

( A ) AÈÜÒºµÄpY?¼ÆºÍBÈÜÒºµÄpY?¼ÆÏàµÈ ( B ) AÈÜÒºµÄpY?¼Æ±ÈBÈÜÒºµÄpY?¼Æ´ó

( C ) A ÈÜÒºµÄpY?¼Æ±ÈBÈÜÒºµÄpY?¼ÆС ( D ) ²»ÄÜÈ·¶¨

25. ÔÚpHΪ10.0µÄ°±ÐÔ»º³åÒºÖÐ, ÒÔ0.01 mol/L EDTA µÎ¶¨Í¬Å¨¶ÈZn2+ÈÜÒºÁ½·Ý¡£ÆäÖÐÒ»·Ýº¬ÓÐ0.2 mol/L ÓÎÀëNH3; ÁíÒ»·Ýº¬ÓÐ0.5 mol/L ÓÎÀëNH3¡£ÔÚÉÏÊöÁ½ÖÖÇé¿öÏÂ, ¶ÔpZn'ÐðÊöÕýÈ·µÄÊÇ ( A )

(A) ÔÚ»¯Ñ§¼ÆÁ¿µãÇ°pZn'ÏàµÈ (B) ÔÚ»¯Ñ§¼ÆÁ¿µãʱpZn'ÏàµÈ

(C) ÔÚ»¯Ñ§¼ÆÁ¿µãºópZn'ÏàµÈ (D) ÔÚÉÏÊöÈýÖÖÇé¿öÏÂpZn'¶¼²»ÏàµÈ 26. EDTAµÎ¶¨½ðÊôÀë×Óʱ, Èô½öŨ¶È¾ùÔö´ó10±¶, pMͻԾ¸Ä±ä ( A ) (A) 1¸öµ¥Î» (B) 2¸öµ¥Î» (C) 10¸öµ¥Î» (D) ²»±ä»¯

27. EDTAµÎ¶¨ÖÐ, ½éÖÊpHÔ½µÍ, Ôò?Y(H)ÖµÔ½_´ó___, K'(MY)ÖµÔ½_С___, µÎ¶¨µÄpM'ͻԾԽ_С___,»¯Ñ§¼ÆÁ¿µãµÄpM'ÖµÔ½__С__¡£

28. ¸ù¾ÝϱíËù¸øÊý¾ÝÍƶÏÓÃEDTAµÎ¶¨Ca2+(ÈÜÒºµÄpH=13)ʱ±íÖи÷µãµÄpCaÖµ¡£ Ũ¶È pCa »¯Ñ§¼ÆÁ¿µãÇ°»¯Ñ§¼ÆÁ¿µã »¯Ñ§¼ÆÁ¿µãºó0.1% 0.1% 0.01mol/L 5.3 6.5 7.7 0.1mol/L 4.3 6.0 7.7 29. ½ðÊôָʾ¼ÁÊÇָʾ½ðÊôÀë×ÓŨ¶È±ä»¯µÄָʾ¼Á£¨¡Ì £©¡£ 2+

30. ÊÔ¸ø³ö¸õºÚTÓÃÓÚEDTAµÎ¶¨MgµÄÌõ¼þºÍÏÖÏó -H+ -H+ H2In- HIn2-

In3-

pKa1 =6.3 pKa2 =11.6 ºìÉ« (À¶É«_É« ) ³ÈÉ« + Mg2+

|| pH=_10_

MgIn+Mg2+(_¾ÆºìÉ«) || +Y

MgY+HIn (ÖÕµã_À¶ _É«) 31. ¸õºÚTָʾ¼ÁÔÚpH=8¡«11·¶Î§Ê¹Óã¬ÆäÄ¿µÄÊÇΪ¼õÉÙ¸ÉÈÅÀë×ÓµÄÓ°Ï죨¡Á £©¡£ 32. ¸õºÚT(EBT)ÊÇÓлúÈõËá, ÆäpKa2=6.3, pKa3=11.6, Mg2+-EBTµÄlgKÎÈ=7.0¡£ÔÚpH=10ʱ, lgK'(Mg-EBT)µÄÖµÊÇ ( B )

(A) 6.4 (B) 5.4 (C) 4.4 (D) 7.0

33£®ÅäλµÎ¶¨ÖУ¬Ö¸Ê¾¼ÁµÄ·â±ÕÏÖÏóÊÇÓÉ£¨ D £©ÒýÆðµÄ £¨A£©Ö¸Ê¾¼ÁÓë½ðÊôÀë×ÓÉú³ÉµÄÂçºÏÎï²»Îȶ¨ £¨B£©±»²âÈÜÒºµÄËá¶È¹ý¸ß

£¨C£©Ö¸Ê¾¼ÁÓë½ðÊôÀë×ÓÉú³ÉµÄÂçºÏÎïÎȶ¨ÐÔСÓÚMYµÄÎȶ¨ÐÔ £¨D£©Ö¸Ê¾¼ÁÓë½ðÊôÀë×ÓÉú³ÉµÄÂçºÏÎïÎȶ¨ÐÔ´óÓÚMYµÄÎȶ¨ÐÔ 34. Ôì³É½ðÊôָʾ¼Á·â±ÕµÄÔ­ÒòÊÇָʾ¼Á±¾Éí²»Îȶ¨£¨¡Á £©¡£ 35£®²úÉú½ðÊôָʾ¼ÁµÄ½©»¯ÏÖÏóÊÇÒòΪ£¨ B £© £¨A£©Ö¸Ê¾¼Á²»Îȶ¨ £¨B£©MInÈܽâ¶ÈС £¨C£©K¨@MIn < K¨@MY £¨D£©K¨@MIn > K¨@MY

36. ½ðÊôָʾ¼ÁµÄ½©»¯ÏÖÏóÊÇÖ¸µÎ¶¨Ê±ÖÕµãûÓгöÏÖ (¡Á )¡£

37. ¸õºÚTָʾ¼Á³£Åä³É¹ÌÌåÊÔ¼Á¶ø²»ÊÇË®ÈÜÒº,ÆäÔ­ÒòÊÇ_Ë®ÈÜÒº²»Îȶ¨Ò×±»Ñõ»¯_, ¼ÓÈëNaClµÄÄ¿µÄÊÇ___×÷Ï¡ÊͼÁ__¡£ 38. ½ðÊôָʾ¼Á PAN ÔÚÈÜÒºÖÐÓÐÈçÏÂƽºâ: pK a1=1.9 pK a2=12.2 H2In+

HIn

In-

»ÆÂÌ »Æ ·Ûºì

ËüÓë½ðÊôÀë×ÓÐγɵÄÂçºÏÎïMInΪºìÉ«, µ±Ê¹ÓÃPAN×÷ָʾ¼Áʱ, pH·¶Î§Ó¦ÊÇ_1.9~12.2 ¡£

ÈôʹÓÃPAN-Cuָʾ¼ÁÒÔEDTAÈÜÒºµÎ¶¨Ca2+, »¯Ñ§¼ÆÁ¿µãÇ°ÈÜÒºÊÇ__ºì__ ÑÕÉ«, »¯Ñ§¼ÆÁ¿µãºóÈÜÒº³Ê_»ÆÂÌ_ÑÕÉ«¡£

39. ÔÚpH=10µÄ°±ÐÔ»º³åÈÜÒºÖÐ,ÒÔ¸õºÚT(EBT)Ϊָʾ¼Á, ÓÃEDTAÈÜÒºµÎ¶¨Ca2+ʱ, ÖÕµã±äÉ«²»ÃôÈñ, ´Ëʱ¿É¼ÓÈëÉÙÁ¿__ MgY _×÷Ϊ¼ä½Ó½ðÊôָʾ¼Á, ÔÚÖÕµãÇ°ÈÜÒº³ÊÏÖ_ºì___É«, ÖÕµãʱÈÜÒº³ÊÏÖ_À¶_É«¡£ 40. ÔÚijһpHÏÂ, ÒÔ2.0¡Á10-4mol/L EDTAµÎ¶¨2.0¡Á10-4mol/L½ðÊôÀë×ÓM, ÉèÆäÌõ¼þÎȶ¨³£ÊýlgK'(MY)=10.0, ¼ì²âÖÕµãʱµÄ?pM=0.40, ÔòEtΪ__0.2 _%¡£ 41£®ÅäλµÎ¶¨ÖмÓÈ뻺³åÈÜÒºµÄÔ­ÒòÊÇ£¨ C £©

£¨A£©EDTAÅäλÄÜÁ¦ÓëËá¶ÈÓÐ¹Ø £¨B£©½ðÊôָʾ¼ÁÓÐÆäʹÓõÄËá¶È·¶Î§ £¨C£©EDTAÓë½ðÊôÀë×Ó·´Ó¦¹ý³ÌÖлáÊͷųöH+ £¨D£©KMY¡¯»áËæËá¶È¸Ä±ä¶ø¸Ä±ä

42. EDTAµÄËáЧӦÇúÏßÊÇ_ lg?Y(H)¡«pH _µÄ¹ØϵÇúÏß¡£ 43£®Êµ¼Ê²â¶¨Ä³½ðÊôÀë×Óʱ£¬Ó¦½«pH¿ØÖÆÔÚ´óÓÚ£¨×îСpH £©ÇÒ£¨Ð¡ÓÚ×î´ópH £©

µÄ·¶Î§Ö®ÄÚ¡£

44. ÂçºÏµÎ¶¨ÖУ¬ÈÜÒºµÄ×î¼ÑËá¶È·¶Î§ÊÇÓÉEDTA¾ö¶¨µÄ£¨ ¡Á £©¡£

45. ÔÚÅäλµÎ¶¨ÖÐ, ÈôÈÜÒºµÄpHÖµ¸ßÓڵζ¨MµÄ×îСpHÖµ, ÔòÎÞ·¨×¼È·µÎ¶¨(¡Á )¡£

46. EDTAµÎ¶¨Ä³½ðÊôÀë×ÓÓÐÒ»ÔÊÐíµÄ×î¸ßËá¶È£¨pHÖµ£©£¬ÈÜÒºµÄpHÔÙÔö´ó¾Í²»ÄÜ׼ȷµÎ¶¨¸Ã½ðÊôÀë×ÓÁË£¨¡Á £©¡£ µÚ°Ë½Ú ÂçºÏµÎ¶¨µÄ·½Ê½ºÍÓ¦ÓÃ

47£®ÔÚÅäλµÎ¶¨ÖУ¬Ö±½ÓµÎ¶¨·¨µÄÌõ¼þ°üÀ¨( C )

£¨A£©lgCM,spKMY¡¯¡Ü8 £¨B£©ÈÜÒºÖÐÎÞ¸ÉÈÅÀë×Ó

£¨C£©ÓбäÉ«ÃôÈñÎÞ·â±Õ×÷ÓõÄָʾ¼Á £¨D £©·´Ó¦ÔÚËáÐÔÈÜÒºÖнøÐÐ

48£®ÂÁÑÎÒ©ÎïµÄ²â¶¨³£ÓÃÅäλµÎ¶¨·¨¡£¼ÓÈë¹ýÁ¿EDTA, ¼ÓÈÈÖó·ÐƬ¿Ìºó£¬ÔÙÓñê׼пÈÜÒºµÎ¶¨¡£¸ÃµÎ¶¨·½Ê½ÊÇ£¨ C£©¡£ £¨A£©Ö±½ÓµÎ¶¨·¨ £¨B£©Öû»µÎ¶¨·¨ £¨C£©·µµÎ¶¨·¨ £¨D£©¼ä½ÓµÎ¶¨·¨

49. EDTAµÎ¶¨Al3+, Zn2+, Pb2+»ìºÏÒºÖеÄAl3+Ó¦²ÉÓà ( C )

(A) Ö±½ÓµÎ¶¨·¨ (B) »ØµÎ·¨ (C) Öû»µÎ¶¨·¨ (D) ¼ä½Ó·¨

50. ÒÑÖªAg+, Ni2+ ÓëEDTAÂçºÏÎïµÄÎȶ¨³£Êý·Ö±ðΪlgK(AgY)=7.32, lgK(NiY)=18.6, Ag+-CN- ÂçºÏÎïµÄlg?2=21.1, Ni2+-CNÂçºÏÎïµÄlg?4=31.3¡£ÓÚº¬Ag+µÄÊÔÒºÖмÓÈë¹ýÁ¿Ni(CN)42-ÂçºÏÎï, È»ºóÔÚpH=10µÄ»º³åÈÜÒºÖÐÒÔEDTAÈÜÒºµÎ¶¨Öû»³öµÄNi2+Á¿¡£ÔÚÉÏÊöÖû»·´Ó¦ÖÐ, Ag+ÓëNi2+µÄÎïÖʵÄÁ¿Ö®±Èn(Ag) : n(Ni)Ϊ (2:1)¡£

51. ÈôÒÔ½ðÊôпΪ»ù×¼Îï, ÒÔ¸õºÚTΪָʾ¼Á±ê¶¨EDTA, ¶øÅäÖÆ´ËEDTAµÄË®Öк¬ÓÐÉÙÁ¿Ca2+, Óô˱궨ºóµÄEDTA²â¶¨CaCO3ÊÔ¼ÁµÄ´¿¶È, Æä½á¹û½«( Æ«¸ß )¡£(ָƫ¸ß, µÍ»òÎÞÓ°Ïì)